⟩ C++ supports …. a) constant pointer b) pointer to a constant c) None of above d) Both of above
d) Both of above
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Why we use the "dynamic_cast" type conversion? a) result of the type conversion is a valid b) to be used in low memory c) result of the type conversion is a invalid d) None of the mentioned
What is the output of this program?
#include <iostream>
using namespace std;
class sample1
{
float i, j;
};
class sample2
{
int x, y;
public
sample2 (int a, int b)
{
x = a;
y = b;
}
int result()
{
return x + y;
}
};
int main ()
{
sample1 d;
sample2 * padd;
padd = (sample2*) &d;
cout < result();
return 0;
}
a) 20
b) runtime error
c) random number
d) c or bWhat is the output of this program?
#include <iostream>
#include <cmath>
using namespace std;
class Complex
{
private
double real;
double imag;
public
Complex(double r = 0.0, double i = 0.0) real(r), imag(i)
{}
double mag()
{
return getMag();
}
operator double ()
{
return getMag();
}
private
double getMag()
{
return sqrt(real * real + imag * imag);
}
};
int main()
{
Complex com(3.0, 4.0);
cout << com.mag();
cout << com;
return 0
}
a) 5 5
b) 4 5
c) 6 6
d) None of the mentionedprogram Output
#include <iostream>
using namespace std;
class sample
{
public
sample(int i) m_i(i) { }
public
int operator()(int i = 0) const
{
return m_i + i;
}
operator int () const
{
return m_i;
}
private
int m_i;
friend int g(const sample&);
};
int f(char c)
{
return c;
}
int main()
{
sample f(2);
cout << f(2);
return 0;
}
a) 3
b) 4
c) 5
d) None of the mentionedHow types are there in user defined conversion? a) 1 b) 2 c) 3 d) 4
What is the output of this program?
#include <iostream>
using namespace std;
int main()
{
double a = 21.09399;
float b = 10.20;
int c ;
c = (int) a;
cout << c ;
c = (int) b;
cout << c ;
return 0;
}
a) 2110
b) 1210
c) 21
d) None of the mentionedWhat is the output of this program?
#include <iostream>
#include <string>
using namespace std;
class test
{
public
operator string ()
{
return "Converted";
}
};
int main()
{
test t;
string s = t;
cout << s << endl;
return 0;
}
a) converted
b) error
c) run time error
d) None of the mentionedPick out the correct syntax of operator conversion. a) operator float()const b) operator float() c) operator const d) None of the mentioned
Output of this program?
#include <iostream>
using namespace std;
class Integer
{
int i;
public
Integer(int ii) i(ii) {}
const Integer
operator+(const Integer& rv) const
{
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv)
{
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main()
{
int i = 1, j = 2, k = 3;
k += i + j;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
}
a) operator+
operator+=
b) operator+=
operator+
c) operator+
operator+
d) None of the mentionedOutput of Program?
#include <iostream>
using namespace std;
class sample
{
public
int x, y;
sample() {};
sample(int, int);
sample operator + (sample);
};
samplesample (int a, int b)
{
x = a;
y = b;
}
sample sampleoperator+ (sample param)
{
sample temp;
temp.x = x + param.x;
temp.y = y + param.y;
return (temp);
}
int main ()
{
sample a (4,1);
sample b (3,2);
sample c;
c = a + b;
cout << c.x << "," << c.y;
return 0;
}
a) 5, 5
b) 7, 3
c) 3, 7
d) None of the mentioned
