⟩ In C++, symbolic constants created using a) const b) enum c) Both of above d) None of above
c) Both of above
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More Questions for you:
How types are there in user defined conversion? a) 1 b) 2 c) 3 d) 4
What is the output of this program?
#include <iostream>
using namespace std;
int main()
{
double a = 21.09399;
float b = 10.20;
int c ;
c = (int) a;
cout << c ;
c = (int) b;
cout << c ;
return 0;
}
a) 2110
b) 1210
c) 21
d) None of the mentionedWhat is the output of this program?
#include <iostream>
#include <string>
using namespace std;
class test
{
public
operator string ()
{
return "Converted";
}
};
int main()
{
test t;
string s = t;
cout << s << endl;
return 0;
}
a) converted
b) error
c) run time error
d) None of the mentionedPick out the correct syntax of operator conversion. a) operator float()const b) operator float() c) operator const d) None of the mentioned
Output of this program?
#include <iostream>
using namespace std;
class Integer
{
int i;
public
Integer(int ii) i(ii) {}
const Integer
operator+(const Integer& rv) const
{
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv)
{
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main()
{
int i = 1, j = 2, k = 3;
k += i + j;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
}
a) operator+
operator+=
b) operator+=
operator+
c) operator+
operator+
d) None of the mentionedOutput of Program?
#include <iostream>
using namespace std;
class sample
{
public
int x, y;
sample() {};
sample(int, int);
sample operator + (sample);
};
samplesample (int a, int b)
{
x = a;
y = b;
}
sample sampleoperator+ (sample param)
{
sample temp;
temp.x = x + param.x;
temp.y = y + param.y;
return (temp);
}
int main ()
{
sample a (4,1);
sample b (3,2);
sample c;
c = a + b;
cout << c.x << "," << c.y;
return 0;
}
a) 5, 5
b) 7, 3
c) 3, 7
d) None of the mentionedWhich of the following operators can't be overloaded? a) b) + c) - d) []
Output of this program?
#include <iostream>
using namespace std;
class myclass
{
public
int i;
myclass *operator->()
{return this;}
};
int main()
{
myclass ob;
ob->i = 10;
cout << ob.i << " " << ob->i;
return 0;
}
a) 10 10
b) 11 11
c) error
d) runtime errorThe output of this program?
#include <iostream>
using namespace std;
ostream & operator<<(ostream & i, int n)
{
return i;
}
int main()
{
cout << 5 << endl;
cin.get();
return 0;
}
a) 5
b) 6
c) error
d) runtime errorOperator overloading is a) making c++ operator works with objects b) giving new meaning to existing operator c) making new operator d) both a & b
