⟩ Which statement skips over the rest of the loop body, causing the next cycle around the loop to begin immediately? a) continue b) break c) next d) none of the mentioned
a) continue
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What is the output of this program no 6?
#include<stdio.h>
#include<pthread.h>
#include<fcntl.h>
int fd;
void *fun_t(void *arg);
void *fun_t(void *arg)
{
char buff[10];
int count;
count = read(fd,buff,10);
printf("%dn",count);
pthread_exit("Bye");
}
int main()
{
pthread_t pt;
void *res_t;
fd = open("san.c",O_RDONLY);
if(pthread_create(&pt,NULL,fun_t,NULL) != 0)
perror("pthread_create");
if(pthread_join(pt,&res_t) != 0)
perror("pthread_join");
return 0;
}
a) 10
b) 0
c) -1
d) segmentation faultWhat is the output of this program no 7?
#include<stdio.h>
#include<pthread.h>
#include<fcntl.h>
void *fun_t(void *arg);
void *fun_t(void *arg)
{
pthread_exit("Bye");
printf("googlen");
}
int main()
{
pthread_t pt;
void *res_t;
if(pthread_create(&pt,NULL,fun_t,NULL) != 0)
perror("pthread_create");
if(pthread_join(pt,&res_t) != 0)
perror("pthread_join");
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a) google
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#include<stdio.h>
#include<pthread.h>
void *fun_t(void *arg);
void *fun_t(void *arg)
{
sleep(1);
}
int main()
{
pthread_t pt;
void *res_t;
if(pthread_create(&pt,NULL,fun_t,NULL) != 0)
perror("pthread_create");
if(pthread_join(pt,&res_t) != 0)
perror("pthread_join");
printf("%sn",res_t);
return 0;
}
a) this process will pause
b) segmentation fault
c) run time error
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For debugging with GDB, the compiled program can be run by the command a) run b) execute c) ./ d) none of the mentioned
In GDB, breakpoints can be set by the command a) break b) b c) both (a) and (b) d) none of the mentioned
Which one of the following string will print first by this program?
#include<stdio.h>
#include<pthread.h>
void *fun_t(void *arg);
void *fun_t(void *arg)
{
printf("Googlen");
pthread_exit("Bye");
}
int main()
{
pthread_t pt;
void *res_t;
if(pthread_create(&pt,NULL,fun_t,NULL) != 0)
perror("pthread_create");
printf("Linuxn");
if(pthread_join(pt,&res_t) != 0)
perror("pthread_join");
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}
a) Linux
b) Google
c) it can not be predicted
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