⟩ What is the output of this program? #!/bin/bash san_var="google" echo "$san_var" echo '$san_var' echo '"$san_var"' echo "'$san_var'" echo $san_var exit 0 a) google $san_var "$san_var" 'google' $san_var b) google google "google" 'google' google c) program will generate an error message d) program will print nothing
a) google
$san_var
"$san_var"
'google'
$san_var
Explanation:
Using double quotes does not affect the substitution of the variable, while single quotes and backslash do.
Output:
root@ubuntu:/home/google# ./test.sh
$san_var
"$san_var"
'google'
$san_var
root@ubuntu:/home/google#
