Do You Have Any Idea What Is The Output Of This Program? #include<stdio.h> #include<stdlib.h> Int Main() { Int *ptr; *ptr = 10; *ptr = 20; Printf("%dn",*ptr); Return 0; } A) 10 B) 20 C) Segmentation Fault D) None Of The Mentioned

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⟩ Do you have any idea what is the output of this program? #include<stdio.h> #include<stdlib.h> int main() { int ptr; ptr = 10; ptr = 20; printf("%dn",ptr); return 0; } a) 10 b) 20 c) segmentation fault d) none of the mentioned

c) segmentation fault

Explanation:

The segmentation fault occurs because memory for the pointer has not been allocated in this program.

Output:

[root@localhost google]# gcc -o san san.c

[root@localhost google]# ./san

Segmentation fault (core dumped)

[root@localhost google]#

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Question and Answer:

Home Linux Shutdown and Startup

⟩ Do you have any idea what is the output of this program? #include<stdio.h> #include<stdlib.h> int main() { int ptr; ptr = 10; ptr = 20; printf("%dn",ptr); return 0; } a) 10 b) 20 c) segmentation fault d) none of the mentioned

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Question and Answer:

Home Linux Shutdown and Startup

⟩ Do you have any idea what is the output of this program? #include<stdio.h> #include<stdlib.h> int main() { int *ptr; *ptr = 10; *ptr = 20; printf("%dn",*ptr); return 0; } a) 10 b) 20 c) segmentation fault d) none of the mentioned

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⟩ Do you have any idea what is the output of this program? #include<stdio.h> #include<stdlib.h> int main() { int ptr; ptr = 10; ptr = 20; printf("%dn",ptr); return 0; } a) 10 b) 20 c) segmentation fault d) none of the mentioned