B. You have a total of 13 letters. Thats 13 elements arranged in 13!different orders. But we have also two Es, Is and Rs and when we count 13! we are considering an E different from the other E. So we have to divide by 2! for the two Es, by 2! for the two Is and by 2! for the two Rs. Answer is : 13!/ (2!2!2!) = 13!/6 = 778377600
Aptitude
Topic: Probability
IN HOW MANY WAYS CAN THE LETTERS OF THE WORD PREUNIVERSITY BE ARRANGED.a.6227020800b.778377600c.1556755200d.3113510400
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