Let p & q be the roots of the first equation. Given that (p-1) & (q-1) are the roots of the second equation.From the first equation we have,Sum of the roots i.e. p+q = -b/a ---(1)Product of the roots i.e. pq = c/a ---(2)From the second equation we have,Sum of the roots i.e. (p-1)+(q-1) = -b/2 ---(3)Product of the roots i.e. (p-1)(q-1) = 1 ---(4)From (4), we get pq - p - q + 1 = 1 i.e. pq = p+qi.e. c/a = -b/a (From (1) & (2))Hence c = -b or b = -cChoice B is the answer
Aptitude
Topic: Equations
The equation formed by decreasing each root of ax^2+bx+c=0 by 1 is 2x^2+bx+2=0, then:(a) a=-b(b) b=-c(c) c=-a(d) b=a+c
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