Relative speed == (45 + 30) km/hr= 75 x5/18 m/sec= 125/6 m/sec.We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.So, distance covered = Length of the slower train.Therefore, Distance covered = 500 m.Required time = 500 x 6 /125 = 24 sec.
Aptitude
Topic: Trains
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.A.12 sec B.24 secC.48 sec D.60 sec
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