Suppose the can initially contains 7x and 5x litres of mixtures A and B respectivelyQuantity of A in mixture left = (7x - 7/12 x 9) litres = (7x - 21/4) litres.Quantity of B in mixture left = (5x - 5/12 x 9) litres = (5x - 15/4) litres.(7x - 21/4) / [(5x - 15/4)+9] = 7/9 = › 28x - 21/20x + 21 = 7/9 =› 252x - 189 = 140x + 147 =› 112x = 336 =’ x = 3.So, the can contained 21 litres of A.
Aptitude
Topic: Mixtures and Alligations
A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially? A. 10 B. 20 C. 21 D. 25
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