It's valid to address it, but not to see what's there. (The really short answer is, "Yes, so don't worry about it.") With most compilers, if you sayint i, a[MAX], j;then either i or j is at the part of memory just after the last element of the array. The way to see whether i or j follows the array is to compare their addresses with that of the element following the array. The way to say this in C is that either& i == & a[ MAX ]is true or& a[ MAX ] == & jis true. This isn't guaranteed; it's just the way it usually works. The point is, if you store something in a[MAX], you'll usually clobber something outside the a array. Even looking at the value of a[MAX] is technically against the rules, although it's not usually a problem. Why would you ever want to say &a[MAX]? There's a common idiom of going through every member of a loop using a pointer. Instead offor ( i = 0; i < MAX; ++i ){ /* do something */;}C programmers often write this:for ( p = a; p < & a[ MAX ]; ++p ){ /* do something */;}The kind of loop shown here is so common in existing C code that the C standard says it must work. C++
Topic: Array
Is it valid to address one element beyond the end of an array?
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