Pointers require a bit of new syntax because when you have a pointer, you need the ability to request both the memory location it stores and the value stored at that memory location. Moreover, since pointers are somewhat special, you need to tell the compiler when you declare your pointer variable that the variable is a pointer, and tell the compiler what type of memory it points to.The pointer declaration looks like this:<variable_type> *<name>; For example, you could declare a pointer that stores the address of an integer with the following syntax:int *points_to_integer;Notice the use of the *. This is the key to declaring a pointer; if you add it directly before the variable name, it will declare the variable to be a pointer. Minor gotcha: if you declare multiple pointers on the same line, you must precede each of them with an asterisk:// one pointer, one regular intint *pointer1, nonpointer1;// two pointersint *pointer1, *pointer2;As I mentioned, there are two ways to use the pointer to access information: it is possible to have it give the actual address to another variable. To do so, simply use the name of the pointer without the *. However, to access the actual memory location, use the *. The technical name for this doing this is dereferencing the pointer; in essence, you're taking the reference to some memory address and following it, to retrieve the actual value. It can be tricky to keep track of when you should add the asterisk. Remember that the pointer's natural use is to store a memory address; so when you use the pointer:call_to_function_expecting_memory_address(pointer);then it evaluates to the address. You have to add something extra, the asterisk, in order to retrieve the value stored at the address. You'll probably do that an awful lot. Nevertheless, the pointer itself is supposed to store an address, so when you use the bare pointer, you get that address back.
C++
Topic: Pointers
What are C++ Pointer Syntax ?
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When local variable’s name is same as member’s name
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