The system will treat negative numbers in 2's complement method.Example:Assume the size of int is 2-bytes(16 bits). The integer value 1 is represented as given below: Binary of 1: 00000000 00000001 (this is for positive value of 1)1's complement of binary 1: 11111111 111111102's complement of binary 1: 11111111 11111111Thy system will store '11111111 11111111' in memory to represent '-1'. If we do left shift (3 bits) on 11111111 11111111 it will become as given below:11111111 11111111 ---(left shift 3 times)---> 11111111 11111000. So, 11111111 11111000 ---(binary to hex)---> FF F8. (Required Answer) Note: How is the negative number obtained from 2's complement value?As stated above, -1 is represented as '11111111 11111111' in memory.So, the system will take 2's complement of '11111111 11111111' to the get the original negative value back. Example: Bit Representation of -1: 11111111 11111111Since the left most bit is 1, it is a negative number. Then the value is1's complement: 00000000 000000002's complement: 00000000 00000001 (Add 1 to the above result) Therefore, '00000000 00000001' = 1 and the sign is negative.Hence the value is -1.
C
Topic: Operators
Assuming a integer 2-bytes, What will be the output of the program?
#include<stdio.h>
int main(){
printf("%xn", -1<<3);
return 0;
}
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