21⟩ If A covers 15 miles in 20 minutes and 20 miles in 30 minutes then find the average speed of A?
average speed=total distance/total time
so answer is 20+15(total dist)/(1/3+1/2)total time in hrs=
35*(6/5)=42miles/hr
“Analytical frequently Asked Questions in various Analytical job Interviews by interviewer. The set of Analytical interview questions here ensures that you offer a perfect answer to the interview questions posed to you. Get preparation of Analytical job interview”
average speed=total distance/total time
so answer is 20+15(total dist)/(1/3+1/2)total time in hrs=
35*(6/5)=42miles/hr
Ans :
2L=1O => 1L=5
THEN,1 1/2 DOZEN=18L
SO,18L=18*5=90CENTS
Each person has contributed 9 Rupees which includes the tips.
9*3 = 25 to shopkeeper + 2 for tips. So question itself is not correct
last month of year is December
SIX
correct answer is 0.0625
because when 1 divide by 2 then we get 0.5 and further divide by 2 then we
get 0.25 and so on
b,d
1min=60sec, so 1min 27 secs is=60+27=87
then 1 month=30days
now, 30days=87secs late
1day = ? x
x = (87*1)/30=2.9 secs
Ans: 2.9 secs per day it will be late.
19
since sum of absolute deviation taken about median is minimum ie median of -5,2,6,10 is 4. Putting x=4 in the fn, ull get 19 as the ans
let no. of fish x catches=p
no. caught by y =r
r=5p.
r+p=42
then p=7,r=35
7 fish caught by x
ans: 0.33 Decresing order(81,1,0.99,0.33)
A completed work in 100 days before and A is 6 times faster than B..
let total days to work is n.
A=6B;
A=(n-100) days taken to complete the work;
where as B=n days ;
A=(B-100)
therefore B=A+100;
A=6(A+100);
A=6A+600;
-600=6A-A
-600=5A
A=-600/5
A=300
B=400;
The next number is 1/16.
Becoz The diff b'ween 1/2 and 1/4 is "+2"
and next 1/4 and 1/8 is "+4"
means 1 1/2 (+2) 1/4 (+4) 1/8 (+8) 1/16
112.5 miles
ans: 1/18 (bcoz it comes 0.062 remain vll come 0.25,0.33,0.16)
answer is =(600*1/2)*10=3000
who wrote dis
does he ever went to school or should i come 2 teach him
speed = distance/time that's the formula
it's not distance = distance * time (u fool)
C. 6
Are you referring to the Cake Cutting problem with 3 people and 2 cuts?
The problem is one of Even-Fairness, how do you divide a cake among 3 people so that each person gets an even amount with only 2 cuts.
The problem is solved via 1 Referee, and 4 Knives.
The Referee holds his Knife and slowly, going from left to right across the cake, draws it to a position for the 1st cut.
The 3 people each have a Knife as well, and position their knife in a position that they think will half the portion of the cake to the right of the Referee's knife.
The first person to call cut, receives that portion of the cake to the left of the Referee's knife, and is removed from the group.
Of the remain 2 people, the person who's knife is farthest to the right of the Referee's knife cuts the remaining portion of the cake and receives the cut portion to the right of their cut. The other person receives the portion to the left of the cut.
37 - 3 = 34
( (mon + tue + wed) / 3 ) - 3 = (tue+wed+thu)/3
( mon + tue + wed -9) / 3 = (tue + wed+ thu) /3
( mon + tue + wed - 9) = (tue + wed + thu )
mon - 9 = thu
(since thu = (4/5) mon )
(5 * thu)/4 - 9 = Thu
Thu = 36
Both boys cross; one returns; the first soldier crosses; the second boy returns; both boys cross; one returns; the second soldier crosses; the second boy returns; both boys cross; one returns; the third soldier crosses n so on :-)