General Aptitude

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“General Aptitude frequently Asked Questions by expert members with experience in General Aptitude. So get preparation for the General Aptitude job interview”



23 General Aptitude Questions And Answers

1⟩ If A earns Rs.450 monthly salary and increment of Rs.25 yearly, similarly B earns Rs.600 salary monthly and Rs.20 increment. when does A earn more than B?

A's monthly income = Rs 450

A's monthly increment = Rs 25/12

B's monthly income = Rs 600

B's monthly increment = Rs 20/12

Let A requires ' x ' month to have A's salary to be equal to B's salary so,

450+25/12+x=600+20/12

X=12.465 years . After 12.465 yrs A's sal becomes more than B's sal....

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4⟩ What is the pattern for MAQ Software company?

1st Round

1.1 First prepare C language --> They will concentrate on

arrays, function and pointers, call by reference and call by

value (30 question) + Aptitude Question from R S Aggarwaal

(20 question)

(50 question 1 hour)

1.2 In Algorithm they will ask two algorithm 45 min.....

just right the logic of it

1--> If few people are electing then every time ur candidate

should win

2--> arrange books in box, if box carry weight == books

weight then take another box..... find the no of box required.

(2 Algorithm 45 minutes)

2nd Round – Two Technical Interview

IN interview one sql query(find employee name whose sal is

b/w 5k and 10k and arrange in ascending order by name), one

question on c like (prime no b/w 50, fibnocci, find the

addition of digit like 456 then u should find 4+5+6 value

etc) one reasonong question(no of square in chess board).

HTML (registration form). (In interview u can write code in

java instead of c)

(prepare on redundancy, joins , ACID property, JDBC connection)

both interview will consist same type of question.

(they will see ur confidence level)

3rd Round

IN HR( Tell abt urself ... why u want to join MAQ, What

special qualities u have?, How many hours u can work? what u

did after B.Tech.)

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9⟩ What is difference between goal and aim?

For example we take this question,

My goal is to answer this question.

My aim is how i am clearly answering the question.

Another example:

My goal is to pass the interview and my aim is the effort

i am taking (iam learning for it )

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15⟩ You have 5 jars of pills. Each pill weighs 10 gram, except for contaminated pills contained in one jar, where each pill weighs 9 gm. Given a scale, how could you tell which jar had the contaminated pills in just one measurement?

1]Suppose there are 5 jars and one physical balance,take any 4 out of them and place 2 jars on each side of the scale remains horizontal,then the remaining jar has the contaminated pills.

2] Else if the balance shifts to one side then the contaminated jar must be on the side which is lifted upwards.so remove one of the jars from either side. if the balance is still tilted to one side then the jar which is left on the side which is tilted is the contaminated jar.

3] If the balance becomes horizontal when you removed it, the jar you removed from the previously tilted jar is the required contaminated jar.

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16⟩ One train leaves Los Angeles at 15mph heading for New York. Another train leaves from New York at 20mph heading for Los Angeles on the same track. If a bird, flying at 25mph, leaves from Los Angeles at the same time as the train and flies back and forth between the two trains until they collide, how far will the bird have traveled?

Actually they should mention distance between the two stations, but i searched in Internet and i found the distance between the stations is 2450 miles.

So the time taken for both trains to meet is

Time taken=distance between them/Relative speed of both trains in opp direction(Sum of speeds)=2450/35=70 hours.

so for these 70 hrs the bird will be travelling here and there. so distance traveled for 70 hrs = 70*25=1750 miles.

So answer is 1750 miles.

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18⟩ Oshkosh did a study of the colors used in African national flags. He found that 38 flags have red, 20 have blue, 13 have both red and blue, and 8 have neither red nor blue. How many flagsa. have red but not blue?b. have blue but not red?c. were included in the study?

n(r)=38

n(b)=20

n(r & b) = 13

n(r+b) = n(r)+n(b)-n(r&b)

= 38+20-13

= 45 (flags with either red or blue)

total flags(study) = 45 + 8(neither red nor blue) = 53

red not blue = 38-13 = 25

blue not red = 20-13 = 7

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