21⟩ 3. 1, 3, 5, 7, __?
9
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9
248
Try trial and error method for the multiple numbers of 7
you will get a number 119 which should get a remainder 6 when divided by 7,5 when divided by 6,4 when divided by 5,3 when divided by 4,2 when divided by 3,1 when divided by 2,