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⟩ What is the sum of all the four digit numbers formed using the digits 0, 1, 2 and 3. None of the two digits should be repeated?

Process of solving

From these four digits '0' cannot be at first place to form four digit number

so we have 1, 2, or 3 can be at thousand's place

keeping one digit at thousand place can have 6 different four digit number

so that means

1000*6 + 2000* 6 + 3000* 6 = 36000

Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place

so that means

100*4 + 200* 4 + 300 * 4= 2400

Now come to tenth's place ...same as hundred

so

10*4 + 20*4 + 30*4= 240

same for unit place

1*4 + 2*4 + 3*4= 24

in last if you add whole the total sum of all possible four digit number formed is 38664

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