1⟩ A building with height D ft shadow up to G. A neighbor building with what height shadow C ft is?
G shadow for height D ftC shadow for height = D*C/G
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G shadow for height D ftC shadow for height = D*C/G
Answer:b:3 P.M.
Assumptions:
Distance between two points where Bus meets auto=x
Distance between the point where bus meets auto for the second time and Amritsar=y
velocity of bus=Vb
velocity of auto=va
vb=x/2
va=x/4
y=0.5*vb=05*x/2
time taken by auto for covering the distance y=y/va=1 Hour
hence time at which auto reaches Amritsar=2 P.M.+1 hour=3 P.M.
this is basically binary operation
n-intersection i.e.LOGICAL AND
U -union i.e. LOGICAL OR
AnB= 01011010
((AnB)uC)=01111111
A - C = 10001011
& (A - C) U B =
1 0 0 0 1 0 1 1
0 0 1 1 0 0 1 1
==========
1 0 1 1 1 0 1 1
HENCE,
ANS = 10111011
ANS-- 11
as A is short by 10- he has shot 1
as B is short by 2 - he has shot 9
9+1=10 10<11
THE OPTIONS ARE
1)55 2)64 3)32 4)53
ANSWER=55
It returns at the 9:58 am
no shankar4u ur wrong in ur calculation..... its ((A-c)B)
ie
197-51=146
146+58 = 204
X = 4 Hence Y = 36
so option 1,2&3 are correct
Its very simple... See by observing that in 2x+3y=100 2x is always even and 100 is also even so u need to have 3y also positive. so within 100 3 can be multiplied by 100/33 times to get an even number. So (b) 33 is the answer.
The Answer is 6:40 AM
The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360).
When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours).
Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM
There are seven children ( 3 girls and 4 boys )
The other condition 1,2 or 2,3 is not possible
Answer A
5-u
5-9
1-I
1-oteat
by substitution , consider x=2/3 & y=3
satisfyng ,x^2y^3=12;(2/3)^2*3^3=12
so 3x+4y=14
First we are taking the l.c.m of 1-10. the result is 2520.
then being the highest prime number 7.
we will divide 2520 by 7. the result will be 360.
which is the least number divisible by all numbers 1-10 other than 7
AM=Mr. Aye
AF= Mrs. Aye
BM=Mr. Bee
BF=Mrs. Bee
The possible sequence of matches can be :
AM(Win) Vs.AF
AM(win) Vs. BM
AM Vs. BF(win) Hence Mrs. Bee never lose.
in c++ programming language #incude<iostream.h> is must so it give error
see it doesn't matter that wat the time is being taken to fill the bucket.after reaching program it waits there for 10ms and back to the programmer in 20 ms.then total time to get the response is 20ms +10 ms=30ms...it's so simple....
Simple Silly question
Go to river catch fish
4*9=36
7*1=7
2*5=10
36+7+10=53...