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332 Aptitude Questions And Answers

222⟩ In a class of 150 students 55 speak English; 85 speak Telugu and 30 speak neither English nor Telugu.1. How many speak both English and Telugu?2. How many speak only Telugu?3. How many speak at least one of the two languages from English and Telugu?

Total=150

English=55

Telugu=85

none/ neither English nor Telugu=30

No. of Students who speak only one or both=150-30=120

so, 120 stud's can speak english or telugu or both.

then,

No. of Stud's speak only English= 120-85(telugu)=35

" " " " Telugu= 120-55=65

Remaining 120-(65+35)=20 stud's can speak both.

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229⟩ A company gives out bonuses based on the amount of income generated by their sales representatives per month. Once the income generated is greater than or equal to $10,000 a bonus of 20% is given. If the income generated is greater than or equal to $8000 but less than $10,000 a bonus of 15% is given. If the income generated is greater than or equal to $5000 then a 3% bonus is given. Read the income generated and print the bonus?

Let x be the income generated.

if x>=10,000 then bonus is 2000Rs therefore the income left is 8,000.

if x>=8,000 and <10,000 then bonus is 1,200Rs therefore the income left is 6,800.

if x>=5000 then bonus is 150Rs therefore the income left is 4,850.

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233⟩ If sachin score 76more than ahzar , and azhar and robin scores sum is 94 and azhar scores 76 less than dravid and dravid score 26 more than robin . What was the total score done in match?

Sachin=Azhar + 76 eq.(1), Azhar + Robin= 94 eq. (2), Dravid= Azhar+76 eq.(3) Dravid = Robin + 26 eq. (4).

Adding eq. (3) and (4). we get

2Dravid = Azhar + Robin + 102 eq. (5). Putting eq. (2) in eq. (5) we get

2Dravid = 94+102 = 196

So. Dravid = 196/2= 98.

Now solving one by one equatin we get. Sachin=98, Robin=72, Azhar=22, Darvid=98.

Adding their scores we get 290 as total score.

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235⟩ What is the missing number in this series? 8 2 14 6 11? 14 6 18 12

The missing number is 5!! the given numbers r:

8,2,14,6,11,?,14,6,18,12

Now...

8-6=2.

14-8=6.

again..after the missing number 14-8=6 n 18-6=12!

And so the missing number shuld be 11-6=5!!

Hopefully the answer is 5...if any body comes up wid another answer..plz do post it!!

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236⟩ Given a collection of points P in the plane, a 1-set is a point in P that can be separated from the rest by a line, i.e the point lies on one side of the line while the others lie on the other side. The number of 1-sets of P is denoted by n1(P). The minimum value of n1(P) over all configurations P of 5 points in the plane in general position (.i.e no three points in P lie on a line) isa) 3b) 5c) 2

a) 3

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237⟩ A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21 . What is the remainder left, when twice the number is divided by 3D?a) 13 b) cannot be determined c) 3 d) 42

suppose the no. is a

a = Dx +8 ...1

a = 3Dy + 21 ...2

So from 1 & 2 we get

D(x-3y) = 13

13 is prime so x-3y has to be 1

let x = 4 and y = 1

We get a = 60

2a = 120

So 120 when divided by 3D = 39

we get remainder as 3

So answer is 3

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240⟩ A man walks at 4 km/hr on plain, then at 3 km/hr uphill and then returns through the same road at 6 km/hr downhill and at 4 km/hr on the plain. It takes altogether 6 hours. So what distance he covered in one way?

total distance 2 reach up d top and return back =24km!!!

let us consider flat land=x km and slope land=y km

speed @ flat land=4kmph,==> 4km=1hr=>1km=1/4hr

thus, for x km==>x/4hr

speed a@ walkin up @ slope=3kmph==>3km=1hr==>1km=1/3 hr

thus for ykm==y/3hr

speed returning back in slope=6kmph==>6km=1hr==>1km=1/6hr

thus for ykm==y/6hr

thus total hour for travel=x/4 +y/3 +y/6 +x/4 =6 hours

solving , x+y=12km

thus total distance to go to top of hill and return back =12+12=24km :)

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