21⟩ If G(0) = -1 G(1)= 1 and G(N)=G(N-1) - G(N-2) then what is the value of G(6)?
ans: -1
bcoz g(2)=g(1)-g(0)=1+1=2
g(3)=1
g(4)=-1
g(5)=-2
g(6)=-1
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ans: -1
bcoz g(2)=g(1)-g(0)=1+1=2
g(3)=1
g(4)=-1
g(5)=-2
g(6)=-1
it need to be 11.cos thr s totally 20 such socks,10 in each color so if we take 11 thr shud be atleat 1pair of same color
The range of x lies between x>3 as well as x>2 w.r to ques. its in existing range
log 0.317=0.3332 and log 0.318=0.3364
then
log 0.319=log0.318+(log0.318-log0.317)
0.3396
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So 10th letter is 'A'
since the distance travelled is same
st=(s+0.5)(4/5)t
on solvin u will get s=2
there is one more equation
st=(s-0.5)(t+5/2)
substitute s=2 in the above eq and find 't' u will get s=2,t=7.5 therefore d=st=15km
ans:15km
assuming bus speed at 27miles / hr
Bus will reach destination at 9.00 am
and will start return journey at 9.30 am
To cover other 27miles at 50% slower speed i.e at 18miles /hr it will take 1hr 30 minutes and will reach at start point at 11am.
here temp is direstly proportional to -t^2/2+8t+3
so at 4pm -4^2/2+4*8+3 is 27
at 9 pm -9^2/2+9*8+3 is 70.5
so diff is 34.5
comming up takes 2 3/8 going down 2 1/8
if they meet at t time.dist. travelled by first one I*tdist. travelled by second one H*ttotal distance is t*(I+H)=Lso t= L/(I+H)meeting point is I*t = I*L/(I+H) dist. from port
R shall be 50% of volume asuumed for
which S is taken 25% of that same volume
let x mile be the distance of picinic spot.onward jrny =x/40 hrreturn jrny = x/30 hrtotal x(1/40+1/30)=8 hr so x=137.14 mile
divide 678 by 7 we ll get 6 as remainder.... again divide d quotient by 7 we get 5 as remainder... again divide quotient getting 6 as remainder...again doing 1 as remainder.... just reverse the order of remainders we got........ we ll get 1656..
Let the salary be x
then 30*x/100 = 300
hence x = 1000
remaining sal 1000-300 = 700
& 1/4 of 700 = 175
so ans= 175
20% is d ans
20*55*65 = 71500 chars
Let the number of sheets required be x here.
Hence, x*65*70 = 71500 chars
or x = 71500/65*70 = 15.71 = 16 sheets(approx)
hence % reduction in sheets = 20%
M=sqrt(100N)
N is increased by 1%
therefore new value of N=N + (N/100)
=101N/100
M=sqrt(100 * (101N/100) )
Hence ,we get
M=sqrt(101 * N)
for an 8-bit memory address memory address : 128 64 32 16 8 4 2 1 1 1 1 1 1 1 1 1 = 253but this can be divided by 11,the next greatest prime number is 1 1 1 1 1 1 0 1 == 251:
The answer is -9*6 - 4*6 = -78
$%$6 = (3)(-1)(3)*6 = -9*6
%$%6 = (-1)(3)(-1)*6 = 3*6
here; (X+Z)/2=114;
(Y+Z)/2=113; from these 2 eq. we have X-Y=2;
therefore suppose that X=2n-1 any odd no. where n=1,2,3.........
y=2n-3 we have to choose Z such that n should be real no.
suppose z=2n-7; therefore (X+Z)/2=114; (2n-1 + 2n-7)/2=114; solving this we get n=59; Y= 115