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332 Aptitude Questions And Answers

245⟩ Pipes are laid by an oil company. If the company has to lay down 3km of pipes and each pipe is 25 meters long, calculate and print the number of pipes needed to cover the distance?

I presume "cober" is a typo for "cover".

3km of pipes is 3000 meters.

3000 meters divided by each pipe length of 25 meters is 120.

Experience and prudence dictates that the oil company should acquire 126 pipes so that there will be no slow-down in the event of breakage or defects. But that's probably not really part of the question.

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249⟩ Ram travels by car from city A to city B heading towards north in 4 hours. From there he travels west to City C in 3 hours. Say his average speed is same during both the courses. Now from C he travels back to A in shortest path possible. How much time he would had taken to reach A from C?

1 hrs

A is the south point, in the question towards north 4hrs and then to C point in west for 3hrs. So, from west to south the time required is 1 hrs

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253⟩ A mixture of 50 liters of milk and water contain 10% of water. How much water must be added to make water 20% in the given mixture?

That's wrong, realize as you add water to the mixture, the volume of the mixture increases as well. Thus if you added 10 ltr of water to the 50 ltr mixture you would get a 60 ltr mixture. made of 45 ltr milk and 15 ltr water. That's 25% water in the mixture, not the 20% water being asked.

So, from the start:

m = Milk

w = Water

x = amount of water to add

For the mixture without any additional water:

w = 5 ltr

m = 45 ltr

Thus :

(45 + (5 + x)) - ((45 + (5 + x)) * 8/10) = (5 + x)

(50 + x) - ((50 + x) * 8/10) = (5 + x)

(50 + x) - (40 + (x * 8/10)) = (5 + x)

(50 + x) = (5 + x) + (40 + (x * 8/10))

50 + x = 45 + x + (x * 8/10)

50 = 45 + (x * 8/10)

5 = x * 8/10

5 * 10/8 = x

6.25 = x

The new mixture = 56.25 ltr

And 20% of 56.25 = 11.25 ltr = 5 (original amount) + 6.25 (amount of water added)

Thus, How much water must be added to make water 20% in the given mixture?

6.25 ltr water

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254⟩ After 10 years A will be twice the age of B before 10 years and now if the difference is 9 years between them then what is the age of B after 10 years?

Let present ages of A and B be x and y respectively.

According to the question

x+10 = 2(y-10) after solving we get

x-2y = -30 eq. (1)

x-y = 9 eq. (2) after solving above equation we will get there present ages as such A = 48 and B = 39.

After 10 years B will be 49 yrs

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256⟩ One year payment to the servant is Rs. 200 plus one shirt. The servant leaves after 9 months and receives Rs.120 and a shirt.Then find the price of the shirt.A. Rs. 80B. Rs. 100C. Rs. 120D. Cannot be determined

Price of Shirt is RS.150.

Explanation:

Let d price of shirt be X

12=200+X

9=120+X

adding above two eqns we get

X=150

Logically if we put the above answer to the problem, we get the problem solved.....

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260⟩ If A can copy 50 pages in 10 hours and A and B together can copy 70 pages in 10 hours, how much time does B takes to copy 26 pages?

A can copy 50 pages in 10 hrs.

A can copy 5 pages in 1hr.(50/10)

now A & B can copy 70 pages in 10hrs.

thus, B can copy 90 pages in 10 hrs.[eqn. is (50+x)/2=70, where x--> no. of pages B can copy in 10 hrs.]

so, B can copy 9 pages in 1hr.

therefore, to copy 26 pages B will need almost 3hrs.

since in 3hrs B can copy 27 pages.

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