61⟩ (998-1)(998-2)(998-3)…………..(998-n)=------- when n>1000?
if u take 998 common then eq. will be
(998)^n(1-1)(1-2)....................(1-n)=(998)^n(0)(-1)......
=0
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332 Aptitude Questions And Answers
62⟩ In which of the system decimal number 184 is = to 1234?
Base=5
4+3a+2a^2+a^3 = 180
ie (a+1)^3 - a^2=181
By virtue we can see 216 - 25 = 181
Thus x=5
63⟩ 3/4+5/36+7/144+..........+17/5784+19/8100 is?
Ans:0.99
=>[1-1/4]+[1/4-1/9]+[1/9-1/16]+...
=>1-1/100
=>0.99
64⟩ The value of ¾ + 5 / 36 + 7 / 144 + …….+17 / 5184 + 19 / 8100?
u can writre the statement as
1-(1/4)=3/4
1/4-(1/9)=5/36
1/9-(1/16)=7/144
so continuing like that we get
1-(1/100)=.99
65⟩ A traveler walks a certain distance. Had he gone half a kilometer an hour faster , he would have walked it in 4/5 of the time, and had he gone half a Kilometer an hour slower, he would have walked 2 ½ hr longer. What is the distance?
there'll be 3 eq...
t - time
d - distance
s - speed
d/t=s
d/(4/5)t=s+1/2
d/(t+(5/2))=s-(1/2)
solve it....
u'll get
d=15...
66⟩ A ship started from a port and moving I miles per hour. And other ships strated from L and moving with H miles per hour.At the place where these two ships will meet|---|---|---|---|---|---|port G H I J K L
Let us consider that the distance betwn each ports be 1 mile because all of them are same ..
By the question we find that the speed of the ship frm the port is equal 2 distance from the port 2 the port I , so he will arrive at I in 1 hr , n similarly the other ship will reach J in 1 hr as port H is 2 mile aways from port
Therefore the meeting point must be betwn the port I and J , (ANS ) ,
By calculation i m getting the metting point as 0.6 miles from the port I and 0.4 miles from the port J..
Formula is ::
Distance covered =6H/ (H+I) for the ship left from the port ..
67⟩ A ship leaves on a long voyage. When it is 18 miles from the shore, a seaplane, whose speed is 10 times that of the ship is sent to deliver mail. How far from the shore does the seaplane catch upo with the ship?
Consider the speed of ship be a then the speed of plane is 10a;
Let t be the time taken by the ship to travel 18 miles then a= 18/t;
Speed of plane =180/t;
Distance covered by the ship during next t' time = 18+ 18*t'/t;
Distance covered by sea plane = 180*t'/t;
Equating both 162*t'/t =18 ;
t'/t = 18/162;
Distance to be covered = 180* 18/162 =20 miles ;
68⟩ The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders.a) 65b) 55c) 50d) 45
let total cost be c= a + nk
where a = fixed cost and
k = variable cost and n = number of boarders
total cost when 25 boarders c = 25*70 = 1750 i.e. 1750 = a + 25k
total cost when 50 boarders c = 50*60 = 3000 i.e. 3000 = a + 50k
solving above 2 eqns, 3000-1750 = 25k i.e. 1250 = 25k i.e. k = 50
therefore, substituting this value of k in either of above 2 eqns we get
a = 500 (a = 3000-50*50 = 500 or a = 1750 - 25*50 = 500)
so total cost when 100 boarders = c = a + 100k = 500 + 100*50 = 5500
so cost per head = 5500/100 = 55
69⟩ Some are 1 kg weights and some are 2 kg weights. The sum of the weights is 260.What is the number of 1kg weights?
There are a total of 150 weights. Let the number of 1 Kg weights be 'x'. Then the number of 2 Kg weights is '150 - x'. The sum of the weights is 260 Kg. ie [x * 1 + (150 - x) * 2] = 260. By solving this you will get 'x' as 40.
70⟩ In a two-dimensional array, X (9, 7), with each element occupying 4 bytes of memory, with the address of the first element X (1, 1) is 3000, find the address of X (8, 5)?
In a two-dimensional array, X (9, 7), with each element occupying 4 bytes of memory, with the address of the first element X (1, 1) is 3000, find the address of X (8, 5).
Ans: 3000 + 4(8 * 7) + 4 * 5
= 3000 + 224+ 20
= 3244
71⟩ A shopkeeper allows discount of 10% on the marked price of an item but charges a sales tax of 8% on the discounted price.If the customer pays Rs.680.40 as the price including the sales tax , what is the marked price?(a)Rs.630 (b)Rs 700 (c)780 (d) none
Ans:700
let the market prise be M.
10% discount of M=M/10
selling prise excluding tax=M-discount=>M-M/10=9M/10
8% tax on discounted prise=9M/10*8/100
=>actual selling prise including tax= 9M/10 + 72M/1000
which is equal to Rs.680.40
=>9M/10 + 72M/1000 = 680.40
=>M=700
72⟩ 1)A, B and C are 8 bit nos. They are as followsA -> 1 1 0 0 0 1 0 1B -> 0 0 1 1 0 0 1 1C -> 0 0 1 1 1 0 1 0 ( - =minus, u=union)Find ((A - C) u B) =?2)My flight takes of at 2pm from a place at 18N 40E and landed 10 Hrs later at a place with coordinates 36N40W.What is the local time when my plane landed?
First of all 'u' indicates "OR "operation. and secondly "subtraction " => addition of two's complement.
taking into account these two steps.
C=00111010
1's complement=11000101
2's complement=1's complement+1
=11000110
thus A-C => A+(2's complement of C) i.e
11000101+11000110
= 10001011 (neglecting the carry)
now (a-c)u b => 10001011 u 00110011
= 10111011
= 187 (ans)
2.) In these questions the north-south longitudes are of no value. What matters is only the east-west latitudes.
here the person goes from 40E to 40W,i.e a total movement of 80 degrees.
so time shift= 24*(80/360) ( a total of 360 degrees).
= 5.33 hrs.
time when he started = 2pm
time taken = 10 hrs
so time of arrival = 12 am
However travelling from east to west=> 12-5.33
= 6.27 pm (ans)
73⟩ In a 8*8 chess board, what is the total number of squares refer model?
its 204
1*1=64
2*2=49
3*3=36
4*4=25
5*5=16
6*6=9
7*7=4
8*8=1
74⟩ Selling a car gains 25% on SP. What %gain on CP?a) 15b) 25c) 33.33d) 47.5
For these problems use formula
profit on SP =x% then profit on CP= x /(100-x) :
profit on CP =x% then profit on SP= x /(100+x);
here profit on CP=25/(100-25)
=25/75
=.3333
% gain on CP is 33.33%
75⟩ 100 glasses are there. A servant has to supply glasses to a person. If he supplies the glasses without any damage he will get 3 paise. Otherwise he will loose 3 paise. At the end of supplying 100 glasses if he gets 270 paise. How many glasses were supplied safely?
Let the number of glasses tat are supplied without any damage be 'x' and the number of glasses supplied with damage be 'y'....He gets 3ps for every glass tat he supplies without any damage, therefore the amount he gets by supplying x glasses is 3x...He loses 3ps for every glass he supplies with damage, therefore the amount he loses is 3y..Total amount he received by supplying 100 glasses is 270ps and the number glasses he supplied is 100
=> 3x-3y=270 and x+y=100...solving these 2 equations, we get x=95 glasses
76⟩ A face of the clock is divided into three parts. First part hours total is equal to the sum of the second and third part. What is the total of hours in the bigger part?
39explain :: the digits shown in the clock are 1,2,3........12. their total sum is 1+2+3+....12 = 78. since it is given that sum of one bigger part is equal to total sum of another 2 smaller parts.=> bigger part = 78/2 = 39.
77⟩ A sum of money is divided among A, B and C such that for each rupee A gets, B gets 65paise and C gets 35paise. If Cs share is Rs.560, the sum is?
Let x = rupees divided among b and c
Given
x * 35/100=560
x*65/100=560*65/35
=> x = 1040
1040+ 560 = 1600
and from the question we can say that a gets double of share which b and c together gets
=> a's share is 3200
78⟩ A person had to multiply two numbers. Instead of multiplying by 35, he multiplied by 53and the product went up by 540. What was the raised product?a) 780b) 1040c) 1590d) 1720
x*53-x*35=540=> x=30 therefore, 53*30=1590 Ans
79⟩ If three tapes are filling a tank of capacity of 500lit with speed of 30lit/sec, 48lit/sec and 36lit/sec. Find after how long time tank will fill?
In 1 sec =30lit+36+48=114
so 500 lit ==500/114sec.
80⟩ Main(){File *fp;fp=fopen("xyz","r");}What does fp point to?
the fp contains a pointer to a FILE structure that holds the details of file xyz....
