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332 Aptitude Questions And Answers

123⟩ One circular array is given(means memory allocation tales place in circular fashion) diamension(9X7) and sarting add. is 3000,What is the address od (2,3)?

I cant draw the pix here so giving the formula

The address would be

B(base add.)+[(i-Row_start)*(Column_limit-Column_start+1)+(j-Column_start)]*width provided that array index start from (1,1).

Here in the formula i,j are the asked index whose address is needed and width is 8 bit as it is integer array.

Now putting value we get

3000+[(2-1)*(7-1+1)+(3-1)]*8=3072

Please reply to this answer. whether it is correct or not.

If the indexing start from 0,0 then diff answer would come out.

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124⟩ Low temperature at the night in a city is 1/3 more than 1/2 hinge as higher temperature in a day. Sum of the low temp and high temp is 100 c. then what is the low temp?

let x be the low temp at night..

and y be the high temp..in day

from the given condition

1/2(x)=1/3(y)

=:3x=2y----------------------(2)

and also given that

x+y=100-------------------(1)

from equation 1 and 2 we get. the answer..

x=40,

so,low temperature is 40 c

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125⟩ One Rectangular Plate with length 8inches, breadth 11 inches and 2 inches thickness is there. What is the length of the circular rod with diameter 8 inches and equal to volume of rectangular plate?

Given volume of the rectangualr plate is equal to volume of circular rod (cylinder).

diameter of the circular rod is 8 inches

so, radius is 4 inches

length of the rectangualr plate is 8 inches

breadth of the rectangualr plate is 11 inches

width of the rectangualr plate is 2 inches

volume of the rectangle is length*breadth*width

volume of the cylinder is PI*radius*radius*length

so,

volume of the rectangle = volume of the cylinder

8*11*2 = (22/7)*4*4*length

length = 8*11*2*(7/22)*(1/4)*(1/4)

length = 1232/352

length = 3.5inches

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126⟩ In a office, 30% are supervisors, 40% are male employees, 60% of supervisors are male. Probability that a random chosen employee is a male or a female?

I would say probability of randomly chosen a male employee is 22% while that of female is 48%.

Base on my understanding of the question,

let 'x' be the total employee (supervisors and ordinary employees)

supervisor: 30% of 'x' = 0.3x

male supervisors: 60% of 0.3x = 0.18x

and female supervisor: 40% of 0.3x = 0.12x

total male employees: 40% of 'x' = 0.4x

therefore, number of ordinary male employee = 0.4x - 0.18x = 0.22x

=> P(male employee) = 0.22x/x = 0.22

i.e. probability of male employee is 22%

total female employees: 60% of 'x' = 0.6x

therefore, number of ordinary female employee = 0.6x - 0.12x = 0.48x

=> P(female employee) = 0.48x/x = 0.48

i.e. probability of female employee is 48%

I hope I've interpreted the question correctly.

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127⟩ A stamp collector arranges his stamps during his free time. When he arranges his stamps in pairs, there is one stamp left. It is the same when he arranges the stamps in groups of 3, 4, 5 and 6. Now, how many stamps will he be left with when he arranges them in groups of 8?

Total stamps are the l.c.m of 3,4,5,6 i.e 60 and 1 is the remainder in all the cases.. so the toal stamp is 60+1=61

now deviding 61 with 8 leaves the remainder 5

so if he want to make it a group of 8 he ll be having 5 stamps left

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131⟩ if a^x=b^y=c^z and b^2=ac then find x+z/xz=?

a^x=b^y=c^z=k(say)

then,

a=k^(1/x),b=k^(1/y),c=k^(1/z);..........(1)

given b^2=ac

{K^(1/y)}^2=k^(1/x)*k^(1/z);

k^(2/y)=k^(1/x+1/z)

2/y=1/x+1/z

2/y=x+z/xz

hence the answer is 2/y "100% it is correct answer"

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132⟩ What is the minimum no of coins of the same size that can be placed on a table so that each coin touches only three, others? All coins must lie flat on the table. What will be the arrangement of the coins?

I belive the answer is 20. 5 sets of four diamonds which when put together form a circle. Hard to eplain without a picture. The each daimond has no space in the middle. Two coins are touching three others and the other two coins are only touching two. But when the ends of these diamonds are put together each coin is touching only 3 others.

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134⟩ How to solve questions which involves arthematic operations on alphabets likexxxxyyyy+zzzz======yxxxz======

R4 R3 R2 R1

x x x x

y y y y

+ z z z z

---------------------------------

y x x x z

A4 A3 A2 A1

--------------------------------

FIRST EQ: FROM ROW R1

X+Y+Z=10+Z ------>(1)

FROM ROW R2:

X+Y+Z+1= X+10;

THEN Y+Z=9------->(2)

FROM ROW R3:

SAME AS ABOVE R2 Y+Z=-1;

FROM ROW R4:

HERE Y VALUE IS 1.

SUM OF X,Y,Z IS LESS THEN 20 WHY BECAUSE X,Y,Z VALUES ARE BELOW TEN AND NOT REPEATABLE.

*X+Y+Z<20 MEANS 20=10 SO WE CAN GET Y VALUE FROM

ROW R4 : Y IS THE CARRY OF (X+Y+Z+1) THIS IS LESS THEN 20 GREATER

THAN 10 SO WE CAN TAKE Y=1;

SUBSTITUTE Y VALUE IN EQ (1): X+Y+Z=Z+10;

1+X=10;

THEN

X=9;

THEN SUBSTITUTE Y VALUE IN EQ(2):

Y+Z=9:

1+Z=9;

THEN Z=8:

RESULT IS:X=9,Y=1,Z=8.

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136⟩ A family, planning a weekend trip, decides to spend not more than a total of 8 hours driving. By leaving early in the morning, they can average 40 miles per hour on the way to their destination. Due to the heavy Sunday traffic, they can average only 30 miles per hour on the return trip. What is the farthest distance from home they can plan to go?(a) 120 miles or less (b) Between 120and 140 miles (c) 140 miles(d) Between 140 and 160 miles (e) 160 miles or more

Since in 8 hour they will travel=8*40=320but due to traffic the will travel is 8*30=240 means 80 less than that. so btwn 240

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139⟩ A man spent 1/6th of his life in child hood, 1/12th of his life as youngster and 1/7th of his life as a bachelor. After five years of his marriage a son was born to him. The son died four years before the father died and at the time of his death his age was half the total age of his father. What is the age of the father?

Here is the solution in details:

Say father's age is x,and son's age is y.we have two variables.We have two equations also.As son's age is half the father's age.So y=x/2 or

x=2y---------------(1)

Now you can read the question like this also.

Next father has spent x/6th of his life in child hood,x/12th of his life as youngster and x/7th of his life as a bachelor,then 5yrs of marriage,then had a son,then son dies,after 4yrs father dies.It gives us this following equation.

x/6+x/12+x/7+5+y+4 = x -------------(2)

Solving (1) & (2) the equations:

=> Y=42

=> X=84

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140⟩ Anand finishes a work in 7 days, Bittu finishes the same job in 8 days and Chandu in 6 days. They take turns to finish the work. Anand on the first day, Bittu on the second and Chandu on the third day and then Anand again and so on. On which day will the work get over?a) 3rdb) 6thc) 9thd) 7th

Ans is d) 7th day

In d 1st day Anand does 1/7th of total work

similarly,

Bithu does 1/8th work in d 2nd day

hence at d end of 3 days, work done = 1/7+1/8+1/6=73/168

remaining work = (168-73)/168 = 95/168

again after 6 days of work, remaining work is = (95-73)/168 = 22/168

and hence Anand completes the work on 7th day.(hope u understood.)

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