201⟩ What is the value of the following series1/7 + 2/72 + 1/73 +2/74 + 1/75 + ______
Following the pattern, the 1's and 2's repeat, and the other numbers increase...
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2/74 + 1/75 + 2/76 + 1/77 + 2/78 + 1/79, etc.
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Following the pattern, the 1's and 2's repeat, and the other numbers increase...
-
2/74 + 1/75 + 2/76 + 1/77 + 2/78 + 1/79, etc.
40 cow can complately eat the grass in 40 days it means there is 40 * 40 = 1600 cow are able to eat the food
for 20 cow = 1600/20 = 80 Days Ans
Let Smallest number be x & largest number be y.
so X/y=8/9
x=8/9y
(x+12)/(y-19)=5/9
(8/9y+12)/(y-19)=5/9
8/9y^2-19*8/9y+12y-12*19-5/9=0
24,4(in unix)
sizeof(str[0])= storage address=inteter=4bytes;
same as sizeof(str)= storage address of 6 =6*4bytes;
for a program
int main(int argc, char **argv) ....
^^^^
sizeof(int) number of arguments are possible
hence 32767 args are possible for a 32 bit computer
10:59pm, 11:54pm
answer is 127
3hrs
1-h/6 = (1-h/4)2
Faster one can do 1/2 of work in one hourslower one can do 1/3 of work in one hourboth they do (1/2+1/3=5/6) th work in one hour.so work will b finished in 6/5=1.2 hour i e 1 hour 12 min.
given.. M=10N^(1/2)................................eqn (1)
dM/dN=10.1/2.N^(-1/2)
or, dM=1/2(10.N^1/2)dN/N
dM=1/2(M)dN/N........................frm eqn (1)
dM/M=1/2.dN/N
put dN/N=1%.........................................frm d qs.
s, dM/M=.5%.......................Answer
1800. i think by laying this the total cost will be much less
zeros are obtained when the product of numbers involves the number '5' or multiples of number '5'.
for example,the product of 1*2*3*4*5=120 i.e there is only one zero bcoz there is only one '5' and no other multiple of '5' is involved in multiplication.
similarly 1*2*3*4*5*6*7*8*9*10=3628800 i.e there are 2 zeros in the end product bcoz there is a '5' and a '10' which is a multiple of '5' are involved.
however in 25*24=600 you see 2 zeros in the end product bcoz 25 can be written as 5*5.
therefore the number of zeros in the end product of numbers 1 to 100 is 23
very simple logic is take julia as 2x
qurban as x
then]
(2x-4)-(x+3)=12
so x=19
so the present sum of ages is 38+19=57
x= banana on first day
for five corresponding days
x+x+6+x+12+x+18+x+24=100
5x+60=100
5x=40
x=8
first day=8
second day=x+6=8+6=14
third day=20
fourth day=26
fifth day=32
This problem doesnt cause any kind of error!!! this is really tricky.. the size of the string "strings" is 7 but it terminates with a char. thus causing the total size to 8.
here in this case some abserd value will come as an output..
if the size of the array is less than 7 then it ll give the error " too many initilization"
and if the size is more than7 then the output ll be perfect and "strings"
In all of the three mechanisms out of 100%
first looses 70% efficiency,
second looses 80% of 30%
efficiency of the first and third loses 60% of 80% of 30%
Then the lack of efficiency is 60% of 80% of 30% = 14.4
total efficiency is (100 - 14.4) = 85.6 (ans)
explanation:
7291 : 7+2= 9 so 9+1 =10
ans is 60 benches
let x=no of benches
y=no of students per bench
given
x*y=600,---------(1)
and given that 10 benches are less hence 2 students are seated more than per bench then
600=(x-10)*(y+2)
600=xy+2x-10y-20------------(2)
since xy=600
then eq(2) is
2x-10y=20
2x-10(600/x)=20
on solving
we get x=60
WE KNOW THAT CIRCUMFERENCE = 2 * 3.142 * RADIUS
AND THEN RADIUS = (CIRCUMFERENCE )/2*3.142
RADIUS = 100/2*3.142
RADIUS = 50/3.142
SO , ANGLE = 20 DEGREES
ANGLE = LENGTH/RADIUS
(20 * 3.142)/180 = (LENGTH*3.142)/ 50 CHANGE DEGREE TO RADIANS
THEREFORE LENGTH = 100/18 = 5.5
18....
procedure...
3,4,6,9,13,......
steps: diffrence between 1st and 2nd no = 1
diffrence between 1st and 2nd no = 2
diffrence between 1st and 2nd no = 3 and so on....
diffrence between 5th no and 4th no = 5
ie; X - 13 = 5
X = 18