⟩ What should be the value of a, in the polynomials x2 - 11x + a and x2 - 14x + 2a, so that these two polynomials have common factors.A. 24B. 1C. -1D. 1/2
(x-b)*(x-c)=x2-11x+a-------(1)
b+c=11
bc=a
(x-b)*(x-d)=x2-14x+2a.........(2)
b+d=14
bd=2a
solving we get
b=8
c=3
d=6
which gives
a=24