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⟩ What should be the value of a, in the polynomials x2 - 11x + a and x2 - 14x + 2a, so that these two polynomials have common factors.A. 24B. 1C. -1D. 1/2

(x-b)*(x-c)=x2-11x+a-------(1)

b+c=11

bc=a

(x-b)*(x-d)=x2-14x+2a.........(2)

b+d=14

bd=2a

solving we get

b=8

c=3

d=6

which gives

a=24

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