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⟩ A work is done by two people in 24 min. one of them can do this work a lonely in 40 min. how much time required to do the same work for the second person?

let A does the work in 40 mins (given)

let B does the work in x mins

amt of work done by A in 1 min = 1/40

amt of work done by B in 1 min = 1/x

amt of work done jointly by both A & B = 1/24

which implies (1/40)+(1/x) = (1/24)

on solvin the above eqn. for x we get

x = 60

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