⟩ Operations Research came into being due to A. medical reasons B. military reasons C. educational reasons D. to improve transportation E. None of the above
B. military reasons
B. military reasons
What will be output if you will execute following c code? #include<stdio.h> void main(){ int arr[][3]={{1,2},{3,4,5},{5}}; printf("%d %d %d",sizeof(arr),arr[0][2],arr[1][2]); }
What will be output if you will execute following c code? #include<stdio.h> void main(){ int a=5,b=10,c=15; int *arr[3]={&a,&b,&c}; printf("%d",*arr[*arr[1]-8]);
Explain is it valid to address one element beyond the end of an array?
What will be output if you will execute following c code? #include<stdio.h> union group{ char xarr[2][2]; char yarr[4]; }; void main(){ union group x={'A','B','C','D'}; printf("%c",x.xarr[x.yarr[2]-67][x.yarr[3]-67]); }
Can you please explain the difference between array_name and &array_name?
What will be output if you will execute following c code? #include<stdio.h> #include<math.h> typedef struct{ char *name; double salary; }job; void main(){ static job a={"TCS",15000.0}; static job b={"IBM",25000.0}; static job c={"Google",35000.0}; int x=5; job * arr[3]={&a,&b,&c}; printf("%s %ft",(3,x>>5-4)[*arr]); } double myfun(double d){ d-=1; return d;
What will be output if you will execute following c code? #include<stdio.h> #include<math.h> double myfun(double); void main(){ double(*array[3])(double); array[0]=exp; array[1]=sqrt; array[2]=myfun; printf("%.1ft",(*array)((*array[2])((**(array+1))(4)))); } double myfun(double d){ d-=1; return d; }
What will be output if you will execute following c code? #include<stdio.h> void main(){ int array[2][3]={5,10,15,20,25,30}; int (*ptr)[2][3]=&array; printf("%dt",***ptr); printf("%dt",***(ptr+1)); printf("%dt",**(*ptr+1)); printf("%dt",*(*(*ptr+1)+2));
Tell me why can't constant values be used to define an array's initial size
What will be output if you will execute following c code? #include<stdio.h> void main(){ static int a=2,b=4,c=8; static int *arr1[2]={&a,&b}; static int *arr2[2]={&b,&c}; int* (*arr[2])[2]={&arr1,&arr2}; printf("%d %dt",*(*arr[0])[1], *(*(**(arr+1)+1)));