When writing complex expressions with several operands, we may have some doubts about which operand is evaluated first and which later. For example, in this expression:a = 5 + 7 % 2we may doubt if it really means:a = 5 + (7 % 2) // with a result of 6, ora = (5 + 7) % 2 // with a result of 0 The correct answer is the first of the two expressions, with a result of 6. There is an established order with the priority of each operator, and not only the arithmetic ones (those whose preference come from mathematics) but for all the operators which can appear in C++. From greatest to lowest priority, the priority order is as follows:Operator Description Grouping :: scope Left-to-right() [] . -> ++ -- dynamic_cast static_cast reinterpret_cast const_cast typeid postfix Left-to-right(type) type casting Right-to-left.* ->* pointer-to-member Left-to-right* / % multiplicative Left-to-right+ - additive Left-to-right<< >> shift Left-to-rightGrouping defines the precedence order in which operators are evaluated in the case that there are several operators of the same level in an expression.All these precedence levels for operators can be manipulated or become more legible by removing possible ambiguities using parentheses signs ( and ), as in this example:a = 5 + 7 % 2;might be written either as:a = 5 + (7 % 2);ora = (5 + 7) % 2;depending on the operation that we want to perform.So if you want to write complicated expressions and you are not completely sure of the precedence levels, always include parentheses. It will also make your code easier to read.
C++
Topic: Operators
Explain about Precedence of operators with example ?
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