⟩ Do you know what is the output of this program? #include<stdio.h> #include<stdlib.h> #include<string.h> int main() { char *ptr; memcpy(ptr,"google",11); printf("%sn",ptr); return 0; } a) google b) segmentation fault c) syntax error d) none of the mentioned
b) segmentation fault
Explanation:
Memory must be allocated to pointer "ptr".
Output:
[root@localhost google]# gcc -o san san.c
[root@localhost google]# ./san
Segmentation fault (core dumped)
[root@localhost google]#