In this type of problems the formulae is 5*x*(12/11)Here x is replaced by the first interval of given time.here i.e 2. In the above problem the given data is between2 and 3 o' clock5*2*12/11 =10*12/11=120/11=10 10/11min.Therefore the hands will coincide at 10 10/11 min.past2.
Aptitude
Topic: Clocks
At what time between 2 and 3 o' clock will be the hands of aclock be together?
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