In this type of problems the formulae is(5*x-30)*12/11x is replaced by the first interval of given time Here i.e 8(5*8-30)*12/11(40-30)*12/1110*12/11=120/11 min=10 10/11 min.Therefore the hands will be in the same straight line but nottogether at 10 10/11 min.past 8.
Aptitude
Topic: Clocks
Find at what time between 8 and 9 o'clock will the hands of aclock be in the same straight line but not together ?
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