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What will be output of the following code ?#includeusing namespace std;class abc{public :void main(){cout<<" Its main function "< }};int main(int c, char **v){abc a;if(c<1){cout<<" Error can not accept it "< exit(1);}cout<<" its in main program "< a.main();return 0;}

The code you have given has many compile time error , but conceptually it will work I have corrected some lines like cout<<" its in main program "< a.main(); it will not work because main the member function is void type it will return nothing while << director needs something.so change void main() to int main() and return 0 at end.exit() function will not work in cout because it returns void type.Also add some lines like printing address of main function,It is possible to take address of main function which is denied by Siva Nookala. It is also possible to call function main in a program but this will call recursion.When any excutable come into run state means process invoke, the OS doesn't actually call the entry-point function main() which you write. Instead, it calls a C/C++ run-time startup function which is added by Linker during linking time.CRT Startup function initializes the CRT library so that you can call functions such as malloc, free, _beginthread,_endthread etc.<br>It also ensures that any global and static C++ objects that you have declared are constructed properly before entry point <br>function main()'s code come into executes. Main() function is nothing but callback thread function for primary thread which created when first time process created by OS and actually this primary thread determines the lifespan of process. Process is nothing but a Kernel object which manage allother resources like memory , other kernel object reference and other devices like input/output.HOPING THIS WILL CLEAR THE , SEE FOLLOWING CORRECT CODE (writeme :mohit.gonduley@gmail.com)#include "stdio.h"#include "stdlib.h"#include "iostream"using namespace std;class abcpublic : int main(){ cout<<" Its main function "<<endl; return 0;};int main(int c, char **v){ abc a; printf(" Address of main Function = %u ",main); if(c<1) { cout<<" Error can not accept it "; } cout<<" its in main program "<<a.main()<<endl;return 0;<br>}

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C++

Topic: I/o operations

What will be output of the following code ?#includeusing namespace std;class abc{public :void main(){cout<<" Its main function "< }};int main(int c, char **v){abc a;if(c<1){cout<<" Error can not accept it "< exit(1);}cout<<" its in main program "< a.main();return 0;}

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C++

Topic: I/o operations

What will be output of the following code ?#includeusing namespace std;class abc{public :void main(){cout<<" Its main function "< }};int main(int c, char **v){abc a;if(c<1){cout<<" Error can not accept it "< exit(1);}cout<<" its in main program "< a.main();return 0;}

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