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You can write to the standard output using code like this: cout << x << y << endl;(Note: this is like calling System.out.println in Java.) The code is evaluated from left to right, so the value of x is written first, then the value of y, then a newline. Therefore, the code given above is equivalent to: cout << x; cout << y; cout << endl;Similarly, you can read from the standard input using code like this: cin >> x >> y;which is equivalent to: cin >> x; cin >> y;(Again, the code is evaluated from left to right, so variable x will be set to the first input value and variable y will be set to the second input value.)Note: 1. Remember that you must #include <iostream> in order to use cin, cout, or endl. 2. To remember which is the input operator and which is the output operator, think of the angle brackets as pointing in the direction the values are flowing; for example, when you write the value of x using "cout << x", the brackets point to cout (so the value is going from x to cout). When you read a value into x you use "cin >> x"; this time, the brackets point to x (so the value is going from cin to x). 3. Both the output operator << and the input operator >> are overloaded; they can be used to write/read any of the primitive types. However, the input operator >> skips all whitespace in the input, so you cannot use it to read a whitespace character (e.g., a space, tab, or newline). 4. It is up to you as the programmer to know what kind of data you are going to read. If the data in the input does not match the type of the variable you are reading into, you will either get a runtime error, or the value you read will be garbage. For example, if you run the following program: #include <iostream> int main() { int x;cout << "enter a number: "; cin >> x; return(0); } and you type a letter instead of a number, you will either get a runtime error, or the value of x will be garbage.

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What will be output of the following code ?#includeusing namespace std;class abc{public :void main(){cout<<" Its main function "< }};int main(int c, char **v){abc a;if(c<1){cout<<" Error can not accept it "< exit(1);}cout<<" its in main program "< a.main();return 0;}

C++

Topic: I/o operations

Explainabout Standard input and output ?

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C++

Topic: I/o operations

Explainabout Standard input and output ?

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