Solutions to Self-Study QuestionsTest Yourself #1 #include <iostream> int main() { int sum = 0; int num; for (int k=1; k<11; k++) { cin >> num; sum += num; } cout << "The sum is: " << sum << endl; return 0; }Test Yourself #2 #include <fstream> void Compare(istream &in1, istream &in2, ostream &out) { char ch1, ch2; while (in1.get(ch1)) { if (!in2.get(ch2) || (ch1 != ch2)) { out << "not equal"; return; } } // here when no more characters in in1 // input files are the same iff there are also no more characters in in2 if (!in2.get(ch2)) out << "equal"; else out << "not equal"; } int main() { ifstream inFile1, inFile2; inFile1.open("Input1"); if (inFile1.fail()) { cerr << "unable to open file Input1 for reading" << endl; exit(1); } inFile2.open("Input2"); if (inFile2.fail()) { cerr << "unable to open file Input2 for reading" << endl; exit(1); } Compare(inFile1, inFile2, cout); return 0; }Note that the order of the two parts of the first "if" condition: if (!in2.get(ch2) || (ch1 != ch2)) ...is very important. Both C++ and Java guarantee that boolean expressions are evaluated left-to-right, so the expression !in2.get(ch2)is evaluated before the expression (ch1 != ch2)This is important since we want to compare the character read in by the call to get to the character in ch1. If the two expressions might be evaluated right-to-left, then the first time through the loop, the expression (ch1 != ch2)would use variable ch2 before it had been initialized. C++
Topic: I/o operations
Write a C++ program that uses a loop to sum ten numbers read from the standard input, and then writes the sum to the standard output ?
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